Solutions
Solution to the billboard below (also my program as a *.zip):
So you visit the website. The solution is that each of the numbers, added across, equal 49. You must find the next set of numbers which add across to 49 within e.
Just a tidbit of my code:
static void Main(string[] args)
{
// starts on the 99th
for(int i=0;i<250;i++){
if(Add(e.Substring(i,10))==49){
Console.WriteLine(e.Substring(i,10));
}
}
Console.ReadLine();
}
static int Add(string nums){
int res = 0;
char[] n = nums.ToCharArray();
foreach(char c in n){
int tmp = Convert.ToInt32(c.ToString());
res += tmp;
}
return res;
}
static string e =
"27182818284590452353602874713526624977572470936999595749669676277240766303535" +
"475945713821785251664274274663919320030599218174135966290435729003342952605956" +
"307381323286279434907632338298807531952510190115738341879307021540891499348841" +
"675092447614606680822648001684774118537423454424371075390777449920695517027618" +
"386062613313845830007520449338265602976067371132007093287091274437470472306969" +
"772093101416928368190255151086574637721112523897844250569536967707854499699679" +
"468644549059879316368892300987931277361782154249992295763514822082698951936680" +
"331825288693984964651058209392398294887933203625094431173012381970684161403970" +
"198376793206832823764648042953118023287825098194558153017567173613320698112509" +
"961818815930416903515988885193458072738667385894228792284998920868058257492796" +
"104841984443634632449684875602336248270419786232090021609902353043699418491463";
The answer there is:
You can find my solution here (again *.zip).
10:05:05 AM 
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